How to make a count in python so that the program ends after a particular number of counts?

Question

I'm a newbie and i need to know how to modify a password guessing program to keep track of how many times the user has entered the password wrong. If it has been entered more than 3 times then it should print " This seems to be complicated" and the program should be ended. The password guessing program is

password="abcd"
while password != "password"
       password = raw_input("Password:")
print "Welcome in"

How should i modify this program to get one as i mentioned earlier? Could anyone guide me? Thank you.

Answer 1

Initialise a count variable to zero and increment it within your loop. You can then use the count within your while loop condition and then after the loop to determine how many tries it took and to print a message.

Answer 2

import sys
counter = 0;
while counter < 3:
    counter += 1
    password = raw_input("Password:")
    if password == "password":
        print "Welcome in"
        break
else:
    print "This seems to be complicated"
    sys.exit(0)

Answer 3

for trial in range(3):
    if raw_input('Password:') == 'password':
        break
else:
    # didn't find password after 3 attempts
    sys.exit(10)
print 'Welcome in'