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Regular expression help.

Answer 1

+1 A:

Here is a decent introductory tutorial for regex in JS.

David Dorward 2010-03-03 11:04:43

Answer 2

+2 A:

You can use the regex:

\w+:\w+

Explanation:
\w - single char which is either a letter(uppercase or lowercase), digit or a _.
\w+ - one or more of above char..basically a word

so \w+:\w+ would match a pair of words separated by a colon.

codaddict 2010-03-03 11:07:16

Answer 3

+1 A:

Try \b(\S+?):(\S+?)\b. Group 1 will capture "Format" and group 2, "Pdf".

A working example:

<html>
<head>
<script type="text/javascript">
function test() {
    var re = /\b(\S+?):(\S+?)\b/g; // without 'g' matches only the first
    var text = "Java Tutorial Format:Pdf With Location:Tokyo  Javascript";

    var match = null;
    while ( (match = re.exec(text)) != null) {
        alert(match[1] + " -- " + match[2]);
    }

}
</script>
</head>
<body onload="test();">

</body>
</html>

A good reference for regexes is https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Global_Objects/RegExp

Jaú 2010-03-03 11:10:30

+1 for the complete example, but -1 for a regex that's too complicated for its own good. ;)

Alan Moore 2010-03-03 11:46:37

Answer 4

A:

([^:]+):(.+)

Meaning: (everything except : one or more times), :, (any character one ore more time)

You'll find good manuals on the net... Maybe it's time for you to learn...

Macmade 2010-03-03 11:10:41

Does not work: take this simple input: "ab cd:ef gh" you'll match 'ab cd' and 'ef gh' instead of 'cd' and 'ef'

codaddict 2010-03-03 11:23:18

This regexp is very wrong, you might make good use of the manuals too.

kemp 2010-03-03 11:48:12

Didn't understand that, sorry. But the regexp works, and you just have to adjust it the following way: ([^:\s]+):([^\s]+)

Macmade 2010-03-03 12:37:44

Answer 5

A:

Use this snippet :

 
$str=" this is pavun:kumar hello world bk:systesm" ;
if ( preg_match_all  ( '/(\w+\:\w+)/',$str ,$val ) )
 {
 print_r ( $val ) ;
 }
 else
 {
 print "Not matched \n";
 }

pavun_cool 2010-03-03 11:11:13

Answer 6

A:

here's the non regex way, in your favourite language, split on white spaces, go through the element, check for ":" , print them if found. Eg Python

>>> s="Java Tutorial Format:Pdf With Location:Tokyo Javascript"
>>> for i in s.split():
...     if ":" in i:
...         print i
...
Format:Pdf
Location:Tokyo

You can do further checks to make sure its really "someword:someword" by splitting again on ":" and checking if there are 2 elements in the splitted list. eg

>>> for i in s.split():
...     if ":" in i:
...         a=i.split(":")
...         if len(a) == 2:
...             print i
...
Format:Pdf
Location:Tokyo

ghostdog74 2010-03-03 11:30:05

Answer 7

A:

Continuing Jaú's function with your additional requirement:

function test() {
    var words = ['Format', 'Location', 'Size'],
            text = "Java Tutorial Format:Pdf With Location:Tokyo Language:Javascript", 
            match = null;
    var re = new RegExp( '(' + words.join('|') + '):(\\w+)', 'g');
    while ( (match = re.exec(text)) != null) {
        alert(match[1] + " = " + match[2]);
    }
}

streetpc 2010-03-03 11:57:40

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Regular expression help.

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