Compare 7 words to eachother to see if 5 of them are equal. How?

Question

I have seven words in the array:

string[7] = {x,x,x,x,x,x,x};

the x is generated from another array:

string[4]={a,b,c,d};

that means each x can be either a or b or c or d. It is randomly generated. this could be an example:

string[7]= {a,a,d,a,a,c,a}

my question is how can I check if there are five x which has the same value?

This is for a poker app Im working on.

Answer 1

You can use Linq to find the largest number of equal items and test if this is 5 or more:

int maxCount = s.GroupBy(x => x).Select(x => x.Count()).Max();

Answer 2

You can group the similar items and find it any group have five or more

from word in new [] { "a", "a", "a", "b", "a", "a", "b" }
group word by word into wordGroup
where wordGroup.Count() >= 5
select wordGroup.Key

Answer 3

You can do it like this:

    List<string> values = new List<string> {"a", "a", "d","a", "a", "c", "a"};

    int count = values.FindAll(id => id == "a").Count();

Answer 4

Sort the array, after that you are sure that if there are five or more of the same value, the middle value is one of them. Count how many:

Array.Sort(words);
int cnt = 0;
Array.ForEach(words, s => { if (s == words[3]) cnt++; });