Super quick question to refresh my mind:
Is:
x -= y;
equivalent to:
x = x - y;
Thanks!
Super quick question to refresh my mind:
Is:
x -= y;
equivalent to:
x = x - y;
Thanks!
No, they are NOT equivalent the way you expressed them.
short x = 0, y = 0;
x -= y; // This compiles fine!
x = x - y; // This doesn't compile!!!
// "Type mismatch: cannot convert from int to short"
The problem with the third line is that -
performs what is called "numeric promotion" (JLS 5.6) of the short
operands, and results in an int
value, which cannot simply be assigned to a short
without a cast. Compound assignment operators contain a hidden cast!
The exact equivalence is laid out in JLS 15.26.2 Compound Assignment Operators:
A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.
So to clarify some of the subtleties:
int x = 5; x *= 2 + 1; // x == 15, not 11
int i = 0; i += 3.14159; // this compiles fine!
arr[i++] += 5; // this only increments i once
Java also has *=
, /=
, %=
, +=
, -=
, <<=
, >>=
, >>>=
, &=
, ^=
and |=
. The last 3 are also defined for booleans (JLS 15.22.2 Boolean Logical Operators).
Not exactly. The reason it was introduced in C was to allow the programmer to do some optimizations the compiler couldn't. For example:
A[i] += 4
used to be compiled much better than
A[i] = A[i] + 4
by the compilers of the time.
And, if "x" has side effects, e.g "x++" then it is wildly different.