In Ruby i do so
asd = 123
asd = '%b' % asd # => "1111011"
views:
151answers:
3
+6
A:
in Python >= 2.6 with bin():
asd = bin(123) # => '0b1111011'
To remove the leading 0b you can just take the substring bin(123)[2:].
bin(x)
Convert an integer number to a binary string. The result is a valid Python expression. Ifxis not a Python int object, it has to define an__index__()method that returns an integer.New in version 2.6.
Felix Kling
2010-03-12 18:11:57
You could also remove the leading '0b' by doing bin(123).strip('0b').
Justin Peel
2010-03-12 18:40:32
@Justin, you should use `lstrip` instead of `strip` as the latter will strip any `0`s from the end of the string as well as the front (thereby changing the value). The slice is probably a better way to go, as it will only ever remove those two characters from the string.
tgray
2010-03-12 20:11:41
@tgray Yes, I agree now that I have thought about it a little more.
Justin Peel
2010-03-12 20:55:45
+7
A:
you can also do string formatting, which doesn't contain '0b':
>>> '{:b}'.format(123) #{0:b} in python 2.6
'1111011'
SilentGhost
2010-03-12 18:16:18
Link: http://docs.python.org/library/string.html#format-specification-mini-language
Felix Kling
2010-03-12 18:18:44
Pretty cool! But it should be `'{0:b}'.format(123)`, and it is for python version ≥ 2.6 only.
Olivier
2010-03-12 18:22:31
A:
bin() works, as Felix mentioned. For completeness, you can go the other way as well.
>>> int('01101100',2)
108
>>> bin(108)
'0b1101100'
>>> bin(108)[2:]
'1101100'
Charles Merriam
2010-03-12 20:45:35