help with regex pattern

Question

i have multiple strings containing a link like:

 <A HREF="http://www.testings2"&gt;testings2&lt;/A&gt;
 <A HREF="http://www.blabla"&gt;blabla&lt;/A&gt;
 <A HREF="http://www.gowick"&gt;gowick&lt;/A&gt;

i want to use a regex pattern that gets the uri within the href.

i could do like:

 /".*?"/

but then the "" will come along. is there a way to just get the uri within the HREF="" without using preg_replace function?

thanks!

Answer 1

preg_match_all('/href="([^"]+)/i', $str, $matches);
var_dump($matches);

Answer 2

$str=<<<EOF
 <A href="http://
www.testings2">testings2</A> blah
 <A HrEF=
"http://www.blabla"&gt;blabla&lt;/A&gt; blah
 <A HREF="http://www.gowick"&gt;gowick&lt;/A&gt;
 <A
HREF="http://www.testing3"&gt;testing3&lt;/A&gt;
<a class="navigation" id="selected" href="http://somewhere.com"&gt;&lt;xsl:value-of
select="title" /></a>
EOF;

$s = preg_split("/<\/A>/i",$str);
$s = preg_replace("/\n+/","",$s);
$uris = preg_grep("/HREF/i",$s);
foreach($uris as $v){
  $fin = explode('">',$v);
  $t=preg_split('/href="/i',$fin[0] );
  print end($t)."\n";
}

output

# php test.php
http://www.testings2
http://www.blabla
http://www.gowick
http://www.testing3
http://somewhere.com

Answer 3

not sure how to apply this in PhP but it works in perl

/<a href="([^"]+)".+/i;

I assume it to be

preg_match( '/<a href="([^"]+)".+/i;', $str, $matches);