tags:

views:

65

answers:

2

I have to modify some code in a application I am working on that is using the array_diff($array1,$array2) method. The problem I am having is it is case sensitive and I need to have it return the correct value if the array values match even if the case is different. I don't want to change the case to lowercase because I need the value returned to keep its case. I'm a little confused as the best method to do this.

A: 

Use

strcasecmp — Binary safe case-insensitive string comparison

<?php
$var1 = "Hello";
$var2 = "hello";
if (strcasecmp($var1, $var2) == 0) {
    echo '$var1 is equal to $var2 in a case-insensitive string comparison';
}
?>

Refer this link for more information

pavun_cool
This is comparing arrays, not strings.
St. John Johnson
see my example above for array comparing, using @pavun_cool's `strcasecmp` and `array_udiff`
JD
not sure that works for my situation, I am comparing two arrays whatever values are not in both get returned and then those are used
dan.codes
+3  A: 

You need: array_udiff and strcasecmp

$result = array_udiff($arr1, $arr2, 'strcasecmp');

E.g.

<?php
$arr1 = array("string","string","string");
$arr2 = array("String","string","sTRING");

$result = array_udiff($arr1, $arr2, 'strcasecmp'); 
print_r($result);
?>

$result should echo array ( )

JD
thanks JD I will try it out.
dan.codes
Worked perfectly, I really appreciate it.
dan.codes