PHP : Pattern Replacement Query.

Question

Currently I have

 Input: e.g., '123456789'.'+'.'987654321'

Desired Pattern:

Output: e.g., '123456789987654321'

How can I achieve this using in php ? I am not through on regex and so what regex would go in preg_replace for this ?

Answer 1

I am not sure if I get your question, but if you're asking how to get rid of the plus symbol:

$input = '123456789+987654321';
$output = preg_replace('/([^+]+)\+([^+]+)/', '$1$2', $input);
echo $output, PHP_EOL;

Answer 2

Try this one.

 $input = "'123456789'.'+'.'987654321'";
 $output = trim("'", preg_replace("/([^+]+)'\.'\+'\.'([^+]+)/", "$1$2", $input));
 // Without RegEx
 $output = trim("'", str_replace("'.'+'.'", "", $input));
 echo $output;

Answer 3

If you only have "123456789+987654321" as the input and want "123456789987654321" as the output, you'd just have to remove the "+" No need for regex:

$output = str_replace("+", "", $input);

If you want to replace this pattern in a bigger string, you can use this regex:

$output = preg_replace("/(\\d+)\\+(\\d+)/", "$1$2", $input);

Note that the "+" has a special meaning in regex and needs to be escaped by a backslash. Additionally, the backslash has a special meaning in PHP strings and needs to be escaped by a backslash itself.

So the above turns into the in-memory string /(\d+)\+(\d+)/, and the regex engine can understand that you mean multiple digits (\d+) and a literal plus (\+).

Answer 4

I think he's actually trying to concatenate

 $customer_id = 123456789;
 $operator_domain = 987654321;

 $Output = $customer_id.$operator_domain;