If you know the trick, you don't even need paper. The number of zeros at the end is how many times it's divisible by 10 . . . in terms of the prime factorization, this is the minimum of the number of times it's divisible by 5 and the number of times it's divisible by 2 (since we need one factor of both 2 and 5 to make a factor of 10). But with factorial we're including every factor less than or equal to 41, so we'll get a lot more factors of 2 than factors of 5. So we only need to worry about how many factors of 5 there are.
So count the numbers that are less than or equal to 41 and divisible by 5:
5,10,15,20,25,30,35,40
There's 8 of them, but don't forget that 25 gives us an extra factor of 5, since it's divisible by 5 twice. So 9 factors of 5 (and thus 9 factors of 10) in all.