highlight the word in the string, if it contains the keyword

Question

how write the script, which menchion the whole word, if it contain the keyword? example: keyword "fun", string - the bird is funny, result - the bird is * funny*. i do the following

     $str = "my bird is funny";
     $keyword = "fun";
     $str = preg_replace("/($keyword)/i","<b>$1</b>",$str);

but it menshions only keyword. my bird is *fun*ny

Answer 1

You can do the following:

 $str = preg_replace("/\b([a-z]*${keyword}[a-z]*)\b/i","<b>$1</b>",$str);

Example:

$str = "Its fun to be funny and unfunny";
$keyword = 'fun';
$str = preg_replace("/\b([a-z]*${keyword}[a-z]*)\b/i","<b>$1</b>",$str);
echo "$str"; // prints 'Its <b>fun</b> to be <b>funny</b> and <b>unfunny</b>'

Answer 2

Try this:

preg_replace("/\w*?$keyword\w*/i", "<b>$0</b>", $str)

\w*? matches any word characters before the keyword (as least as possible) and \w* any word characters after the keyword.

And I recommend you to use preg_quote to escape the keyword:

preg_replace("/\w*?".preg_quote($keyword)."\w*/i", "<b>$0</b>", $str)

Answer 3

Basically the same thing as Gumbo.

preg_replace("/\w*{$keyword}\w*/i", "<b>$0</b>", $str);