views:

276

answers:

4

In php how can I access an array's values without using square brackets around the key? My particular problem is that I want to access the elements of an array returned by a function. Say function(args) returns an array. Why is $var = function(args)[0]; yelling at me about the square brackets? Can I do something like $var = function(args).value(0); or am I missing something very basic?

+1  A: 

In PHP, when getting an array as a function result, you unfortunately have to do an extra step:

$temp_array = function($args);
$var = $temp_array[0];

For objects, this has been relaxed in PHP 5. You can do:

$echo function($args)->property;

(provided function returns an object of course.)

Pekka
It sucks but this is the only way to do this. One of the many reasons to hate PHP.
Luke Magill
@Luke true, but not *that* bad imo. Who knows, it may get fixed in PHP 7 :)
Pekka
@Luke - that's a bit strong isn't it?
nickf
A: 
function getKey($array, $key){
    return $array[$key];
}

$var = getKey(myFunc(args), $key);

There is no way to do this without adding a user function unfortunately. It is just not part of the syntax.

You could always just do it the old fashion way

$array = myFunc();
$value = $array[0];
Chacha102
+6  A: 

As the others have said, you pretty much have to use a temporary variable:

$temp = myFunction();
$value = $temp[0];

But, if know the structure of the array being returned it is possible to avoid the temporary variable.

If you just want the first member:

$value = reset(myFunction());

If you want the last member:

$value = end(myFunction());

If you want any one in between:

// second member
list(, $value) = myFunction();

// third
list(, , $value) = myFunction();

// or if you want more than one:

list(, , $thirdVar, , $fifth) = myFunction();
nickf
Hey, clever! `list()` never ceases to amaze me. +1.
Pekka
reset() and end() require the arguments be references. You get an E_STRICT notice in recent versions of php.
chris
yes, i have been doing this with temporary variables, but was wondering whether i really needed to. now i'm just wondering _why_ i have to. but in any case your list() usage is pretty clever. thanks!
amb
A: 

What exactly matches your expecting is:

echo pos(array_slice($a=myFunc(), pos(array_keys(array_keys($a), 'NameOfKey'));

answered Kinetix Kin, Taipei

Kinetix Kin