views:

705

answers:

4

In the following model:

 class header(models.Model):
    title = models.CharField(max_length = 255)
    created_by = models.CharField(max_length = 255)

    def __unicode__(self):
      return self.id()

class criteria(models.Model):
   details =   models.CharField(max_length = 255)
   headerid = models.ForeignKey(header)

   def __unicode__(self):
     return self.id()

class options(models.Model):
 opt_details =   models.CharField(max_length = 255)
 headerid = models.ForeignKey(header)

 def __unicode__(self):
   return self.id()

If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO

How do i query criteria and options tables to get all the values related to header table id=1

Also can some one please suggest a good link for queries examples,

Thanks..

+3  A: 

First of all, don't use id in the names, because it is confusing. That field isn't the ID, it is the object itself. (If you have a field ref it automatically creates a field ref_id)

options.objects.filter(header=a_header)

You query it like any value, where some header instance is the value you are filtering on.

ironfroggy
+1  A: 

I would suggest trying to us a coding style and naming convention that is more like you see in the Django documentation for Models. Something more like this:

class Header(models.Model):
    ...

class Criteria(models.Model):
    details = model.CharField(max_length=255)
    header = models.ForeignKey(Header)

And then query them as needed:

# find Criteria for a given header
value_mart = Header.objects.get(id=1)

# ... via an instance of Header.
value_mart.criteria_set.all()

# ... or with a filter().
Criteria.objects.filter(header=value_mart)
Criteria.objects.filter(header_id=1)

The documentation for many-to-one relationships also references a usage example.

istruble
+2  A: 

Ironfroggy is right, but there is another more obvious way to get the relevant options and criteria objects. Django automatically creates a 'reverse relation' for every foreign key pointing at a model, and that is usually the name of the related model plus _set. So:

mycriteria.options_set.all()
mycriteria.header_set.all()

will give you all the options and header objects related to a criteria object mycriteria.

Also, a note on style: as ironfroggy pointed out, you shouldn't use id in the foreign key fields, but also you should use Capitalised style for your model classes, so you can see a difference between the class Criteria and a particular instance criteria.

In terms of links, the Django documentation is excellent and explains all of this.

Daniel Roseman
+1  A: 

Sounds like you are looking for Following relationships "backward".

You can get the header object you want to filter by, and use something like

obj = Header.objects.get(title="value-mart", "createdby=CEO")
obj.criteria_set.all()

Look at the documentation for more detailed info

Flávio Amieiro