I'm trying to take the data returned from:
http://ipinfodb.com/ip_query.php?ip=74.125.45.100&timezone=true
Into a dict in a fast and easy way. What's the best way to do this?
Thanks.
I'm trying to take the data returned from:
http://ipinfodb.com/ip_query.php?ip=74.125.45.100&timezone=true
Into a dict in a fast and easy way. What's the best way to do this?
Thanks.
xml.etree
from standard library starting from python2.5. look also at lxml
which has the same interface. I don't "dived in" to much but i think that this is also applicable to python >= 2.5 too.
Edit:
This is a fast and really easy way to parse xml, don't really put data to a dict but the api is pretty intuitive.
Using xml
from the standard Python library:
import xml.etree.ElementTree as xee
contents='''\
<?xml version="1.0" encoding="UTF-8"?>
<Response>
<Ip>74.125.45.100</Ip>
<Status>OK</Status>
<CountryCode>US</CountryCode>
<CountryName>United States</CountryName>
<RegionCode>06</RegionCode>
<RegionName>California</RegionName>
<City>Mountain View</City>
<ZipPostalCode>94043</ZipPostalCode>
<Latitude>37.4192</Latitude>
<Longitude>-122.057</Longitude>
<TimezoneName>America/Los_Angeles</TimezoneName>
<Gmtoffset>-25200</Gmtoffset>
<Isdst>1</Isdst>
</Response>'''
doc=xee.fromstring(contents)
print dict(((elt.tag,elt.text) for elt in doc))
Or using lxml
:
import lxml.etree
import urllib2
url='http://ipinfodb.com/ip_query.php?ip=74.125.45.100&timezone=true'
doc = lxml.etree.parse( urllib2.urlopen(url) ).getroot()
print dict(((elt.tag,elt.text) for elt in doc))
I would use the xml.dom builtin, something like this:
import urllib
from xml.dom import minidom
data = urllib.urlopen('http://ipinfodb.com/ip_query.php?ip=74.125.45.100&timezone=true')
xml_data = minidom.parse(data)
my_dict ={}
for node in xml_data.getElementsByTagName('Response')[0].childNodes:
if node.nodeType != minidom.Node.TEXT_NODE:
my_dict[node.nodeName] = node.childNodes[0].data
Try this recipe: http://code.activestate.com/recipes/410469-xml-as-dictionary/