How to Reassign value of StringBuffer?

Question

How can we re assign the value of a StringBuffer or StringBuilder Variable?

StringBuffer sb=new StringBuffer("teststr");

Now i have to change the value of sb to "testString" without emptying the contents. I am looking at a method which can do this assignment directly without using separate memory allocation.I think we can do it only after emptying the contents.

Answer 1

What do you mean with "reassign"? You can empty the contents by using setLength() and then start appending new content, if that's what you mean.

Edit: For changing parts of the content, you can use replace().

Generally, this kind of question can be easily answered by looking at the API doc of the classes in question.

Answer 2

You can convert to/from a String, as follows:

 StringBuffer buf = new StringBuffer();
 buf.append("s1");
 buf.append("s2");

 StringBuilder sb = new StringBuilder(buf.toString());
 // Now sb, contains "s1s2" and you can further append to it

Answer 3

You can use a StringBuilder in place of a StringBuffer, which is typically what people do if they can (StringBuilder isn't synchronized so it is faster but not threadsafe). If you need to initialize the contents of one with the other, use the toString() method to get the string representation. To recycle an existing StringBuilder or StringBuffer, simply call setLength(0).

Edit
You can overwrite a range of elements with the replace() function. To change the entire value to newval, you would use buffer.replace(0,buffer.length(),newval). See also:

• StringBuilder
• StringBuffer

Answer 4

You might be looking for the replace() method of the StringBuffer:

StringBuffer sb=new StringBuffer("teststr");
sb.replace(0, sb.length() - 1, "newstr");

Internally, it removes the original string, then inserts the new string, but it may save you a step from this:

StringBuffer sb=new StringBuffer("teststr");
sb.delete(0, sb.length() - 1);
sb.append("newstr");

Using setLength(0) reassigns a zero length StringBuffer to the variable, which, I guess, is not what you want:

StringBuffer sb=new StringBuffer("teststr");
// Reassign sb to a new, empty StringBuffer
sb.setLength(0);
sb.append("newstr");

Answer 5

sb.setLength(0);
sb.append("testString");

Answer 6

It should first be mentioned that StringBuilder is generally preferred to StringBuffer. From StringBuffer's own API:

As of release JDK 5, this class has been supplemented with an equivalent class designed for use by a single thread, StringBuilder. The StringBuilder class should generally be used in preference to this one, as it supports all of the same operations but it is faster, as it performs no synchronization.

That said, I will stick to StringBuffer for the rest of the answer because that's what you're asking; everything that StringBuffer does, StringBuilder also... except synchronization, which is generally unneeded. So unless you're using the buffer in multiple threads, switching to StringBuilder is a simple task.

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The question

StringBuffer sb = new StringBuffer("teststr");

"Now i have to change the value of sb to "testString" without emptying the contents"

So you want sb to have the String value "testString" in its buffer? There are many ways to do this, and I will list some of them to illustrate how to use the API.

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The optimal solution: it performs the minimum edit from "teststr" to "testString". It's impossible to do it any faster than this.

StringBuffer sb = new StringBuffer("teststr");
sb.setCharAt(4, 'S');
sb.append("ing");
assert sb.toString().equals("testString");

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This needlessly overwrites "tr" with "tr".

StringBuffer sb = new StringBuffer("teststr");
sb.replace(4, sb.length(), "String");
assert sb.toString().equals("testString");

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This involves shifts due to deleteCharAt and insert.

StringBuffer sb = new StringBuffer("teststr");
sb.deleteCharAt(4);
sb.insert(4, 'S');
sb.append("ing");
assert sb.toString().equals("testString");

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This is a bit different now: it doesn't magically know that it has "teststr" that it needs to edit to "testString"; it assumes only that the StringBuffer contains at least one occurrence of "str" somewhere, and that it needs to be replaced by "String".

StringBuffer sb = new StringBuffer("strtest");
int idx = sb.indexOf("str");
sb.replace(idx, idx + 3, "String");
assert sb.toString().equals("Stringtest");

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Let's say now that you want to replace ALL occurrences of "str" and replace it with "String". A StringBuffer doesn't have this functionality built-in. You can try to do it yourself in the most efficient way possible, either in-place (probably with a 2-pass algorithm) or using a second StringBuffer, etc.

But instead I will use the replace(CharSequence, CharSequence) from String. This will be more than good enough in most cases, and is definitely a lot more clear and easier to maintain. It's linear in the length of the input string, so it's asymptotically optimal.

String before = "str1str2str3";
String after = before.replace("str", "String");
assert after.equals("String1String2String3");

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Discussions

"I am looking for the method to assign value later by using previous memory location"

The exact memory location shouldn't really be a concern for you; in fact, both StringBuilder and StringBuffer will reallocate its internal buffer to different memory locations whenever necessary. The only way to prevent that would be to ensureCapacity (or set it through the constructor) so that its internal buffer will always be big enough and it would never need to be reallocated.

However, even if StringBuffer does reallocate its internal buffer once in a while, it should not be a problem in most cases. Most data structures that dynamically grows (ArrayList, HashMap, etc) do them in a way that preserves algorithmically optimal operations, taking advantage of cost amortization. I will not go through amortized analysis here, but unless you're doing real-time systems etc, this shouldn't be a problem for most applications.

Obviously I'm not aware of the specifics of your need, but there is a fear of premature optimization since you seem to be worrying about things that most people have the luxury of never having to worry about.

Answer 7

Indeed, I think replace() is the best way. I checked the Java-Source code. It really overwrites the old characters.

Here is the source code from replace():

public AbstractStringBuffer replace(int start, int end, String str)
  {
    if (start < 0 || start > count || start > end)
      throw new StringIndexOutOfBoundsException(start);

    int len = str.count;
    // Calculate the difference in 'count' after the replace.
    int delta = len - (end > count ? count : end) + start;
    ensureCapacity_unsynchronized(count + delta);

    if (delta != 0 && end < count)
      VMSystem.arraycopy(value, end, value, end + delta, count - end);

    str.getChars(0, len, value, start);
    count += delta;
    return this;
  }