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views:

294

answers:

6

Hi,

I'm trying to read a java file and display in console the package, class and method name. something like this:

File: Test.java

package tspec.test;

public class Test {
   public void addTest () {}
   public void deleteTest () {}
}

Output:

package name: tspec.test
class name: Test
method name:
addTest
deleteTest

Thanks in advance :)

A: 

You need to use Regular Expression (RegEx) to read that file.

Maksim
Wrong. It is not possible to do this using regular expressions. (Functions have nested braces) You need a stack-based parser.
SLaks
A: 

The only difficult is the java code may not be well formatted. like the function declaration can be spread on multiple lines.

The ultimate solution is to create an automata to tokenize the source code first and then apply some compiler technique to grab what you want from the parsed data.

sza
Regular expressions can handle multiple lines, though I agree on the ultimate solution being a parser.
Marcus Adams
+3  A: 

It's purpose is to introspect Java code and report back about it's contents. With Reflection you can do things like :

 Class.forName(className).getDeclaredMethods();
  • Java also has the Java Mirror API with similiar functionality, but is not as commonly used.

Both of these solutions require no 3rd party libraries or tools.

rlb.usa
A: 

We use PMD Java code analyzer to solve similar problem. It is useful.

http://pmd.sourceforge.net/

Kenji
A: 

You don't have to do this by parsing the Java file yourself! Java already contains a way of getting information about its own classes, methods, and packages: it's called reflection.

Have a look at the java.lang.Class class. Each instance of this class represents a particular Java class, and contains methods to return the class name, the package it lives in, the methods it contains, and lots more information.

Also worth looking at is the java.lang.reflect package, since some of the methods of Class return types from this package. The package contains classes to represent things like methods, types, fields, and so on.

To obtain a Class instance of your Test class, you can use the following code:

Class<?> testclass = Class.forName("tspec.test.Test");

This returns a class of an unknown type, which is what the question mark inside the angle brackets means if you're not familiar with generics. Why the type of the class instance is unknown is because you specify the class name with a string, which is parsed at runtime. At compile-time, Java cannot be sure that the string passed to forName even represent a valid class at all.

However, testclass as defined above will be fine for getting the class's name, methods, and containing package.

isme
I think the poster has access to a .java file and not a .class file.
binil
+1  A: 

This can be accomplished using the Java Compiler API (introduced in Java 6). Unfortunately, this solution is limited to Sun's JDK. Therefore, you will have to have that JDK installed and you must include its tools.jar file in your class path.

public void displayInformation(File javaSourceFile) throws Exception {
    JavaCompiler compiler = ToolProvider.getSystemJavaCompiler();

    // The file manager locates your Java source file for the compiler. Null arguments indicate I am comfortable with its default behavior.
    StandardJavaFileManager fileManager = compiler.getStandardFileManager(null, null, null);

    // These will be parsed by the compiler
    Iterable<? extends JavaFileObject> fileObjects = fileManager.getJavaFileObjects(javaSourceFile);

    // Creates a new compilation task. This doesn't actually start the compilation process.
    // Null arguments indicate I am comfortable with its default behavior.
    CompilationTask task = compiler.getTask(null, null, null, null, null, fileObjects);

    // Cast to the Sun-specific CompilationTask.
    com.sun.tools.javac.api.JavacTaskImpl javacTask = (com.sun.tools.javac.api.JavacTaskImpl) task;

    // The Sun-specific JavacTaskImpl can parse the source file without compiling it, returning 
    // one CompilationUnitTree for each JavaFileObject given to the compiler.getTask call (only one in our case).
    Iterable<? extends CompilationUnitTree> trees = javacTask.parse();
    CompilationUnitTree tree = trees.iterator().next();

    // Create a class that implements the com.sun.source.tree.TreeVisitor interface.
    // The com.sun.source.util.TreeScanner is a good choice because it already implements most of the logic.
    // We just override the methods we're interested in.
    class MyTreeVisitor extends TreeScanner<Void, Void> {

        @Override
        public Void visitClass(ClassTree classTree, Void p) {
            System.out.println("class name: " + classTree.getSimpleName());
            System.out.println("method name:");
            return super.visitClass(classTree, p);
        }

        @Override
        public Void visitMethod(MethodTree methodTree, Void p) {
            System.out.println(methodTree.getName());
            return super.visitMethod(methodTree, p);
        }

    }

    tree.accept(new MyTreeVisitor(), null);
}

When I pass this method a File whose content is your sample, I receive this output:

class name: Test
method name:
addTest
deleteTest

Unfortunately, I haven't yet figured out where the package name is stored.

Adam Paynter