bash script variable inside variable

Question

x=1
c1=string1
c2=string2
c3=string3

echo $c1
string1

I'd like to have the output be string1 by using something like: echo $(c($x))

So later in the script I can increment the value of x and have it output string1, then string2 and string3.

Can anyone point me in the right direction?

Answer 1

if you have bash 4.0, you can use associative arrays.. Or you can just use arrays. Another tool you can use is awk

eg

awk 'BEGIN{
  c[1]="string1"
  c[2]="string2"
  c[3]="string3"
  for(x=1;x<=3;x++){
    print c[x]
  }
}'

Answer 2

See the Bash FAQ: How can I use variable variables (indirect variables, pointers, references) or associative arrays?

To quote their example:

realvariable=contents
ref=realvariable
echo "${!ref}"   # prints the contents of the real variable

To show how this is useful for your example:

function get_c() { local tmp; tmp="c$x"; echo ${!tmp}; }
x=1
c1=string1
c2=string2
c3=string3
echo $(get_c)

If, of course, you want to do it the Right Way and just use an array:

c=( "string1" "string2" "string3" )
x=1
echo "${c[$x]}"

Note that these arrays are zero-indexed, so with x=1 it prints string2; if you want string1, you'll need x=0.

Answer 3

Try this:

eval echo \$c$x

Like others said, it makes more sense to use array in this case.