views:

7696

answers:

13

First: I'm a beginner in python.

How can I fetch more than 1000 record from data store and put all in one single list to pass to django?

+16  A: 

You can't.

Part of the FAQ states that there is no way you can access beyond row 1000 of a query, increasing the "OFFSET" will just result in a shorter result set,

ie: OFFSET 999 --> 1 result comes back.

From Wikipedia:

App Engine limits the maximum rows returned from an entity get to 1000 rows per Datastore call. Most web database applications use paging and caching, and hence do not require this much data at once, so this is a non-issue in most scenarios.[citation needed] If an application needs more than 1,000 records per operation, it can use its own client-side software or an Ajax page to perform an operation on an unlimited number of rows.

From http://code.google.com/appengine/docs/whatisgoogleappengine.html

Another example of a service limit is the number of results returned by a query. A query can return at most 1,000 results. Queries that would return more results only return the maximum. In this case, a request that performs such a query isn't likely to return a request before the timeout, but the limit is in place to conserve resources on the datastore.

From http://code.google.com/appengine/docs/datastore/gqlreference.html

Note: A LIMIT clause has a maximum of 1000. If a limit larger than the maximum is specified, the maximum is used. This same maximum applies to the fetch() method of the GqlQuery class.

Note: Like the offset parameter for the fetch() method, an OFFSET in a GQL query string does not reduce the number of entities fetched from the datastore. It only affects which results are returned by the fetch() method. A query with an offset has performance characteristics that correspond linearly with the offset size.

From http://code.google.com/appengine/docs/datastore/queryclass.html

The limit and offset arguments control how many results are fetched from the datastore, and how many are returned by the fetch() method:

  • The datastore fetches offset + limit results to the application. The first offset results are not skipped by the datastore itself.

  • The fetch() method skips the first offset results, then returns the rest (limit results).

  • The query has performance characteristics that correspond linearly with the offset amount plus the limit.

What this means is

If you have a singular query, there is no way to request anything outside the range 0-1000.

Increasing offset will just raise the 0, so

LIMIT 1000  OFFSET 0

Will return 1000 rows,

and

LIMIT 1000 OFFSET 1000

Will return 0 rows, thus, making it impossible to, with a single query syntax, fetch 2000 results either manually or using the API.

The only plausible exception

Is to create a numeric index on the table, ie:

 SELECT * FROM Foo  WHERE ID > 0 AND ID < 1000 

 SELECT * FROM Foo WHERE ID >= 1000 AND ID < 2000

If your data or query can't have this 'ID' hardcoded identifier, then you are out of luck

Kent Fredric
Thats I know. But How I can fetch 1000 by 1000 and create 1 list with 2000?
Zote
list1 = first querylist2 = second querylist1 += list2
Tom Leys
Tom: its pointless if second query, due to database limits, is guaranteed to return 0 rows.
Kent Fredric
Note that this answer is now somewhat out of date: The __key__ pseudo-property is now available for sorting and filtering, which allows you to iterate through arbitrarily large result sets piecewise.
Nick Johnson
It is possible using jgeewax's method.
bentford
+8  A: 

The 1000 record limit is a hard limit in Google AppEngine.

This presentation http://sites.google.com/site/io/building-scalable-web-applications-with-google-app-engine explains how to efficiently page through data using AppEngine.

(Basically by using a numeric id as key and specifying a WHERE clause on the id.)

jakber
A: 

To add the contents of the two queries together:

list1 = first query
list2 = second query
list1 += list2

List 1 now contains all 2000 results.

Tom Leys
Thats fine in a *normal* database, but not in GAE with GQL. GQL has a hard limit. LIMIT/OFFSET based increasing won't help you, they have to be *different* queries, ie: different WHERE conditions.
Kent Fredric
I agree with (and have upvoted) your answer. My point was to focus on the python question. Once you have two lists (using the different where conditions) you need to merge them. It's extraordinarily simple but a part of his question you missed.
Tom Leys
It might be good to warn him that the size of any GAE object may also limited. During the beta it was 1 megabyte.
Thomas L Holaday
+15  A: 

Every time this comes up as a limitation, I always wonder "why do you need more than 1,000 results?" Did you know that Google themselves doesn't serve up more than 1,000 results? Try this search: http://www.google.ca/search?hl=en&amp;client=firefox-a&amp;rls=org.mozilla:en-US:official&amp;hs=qhu&amp;q=1000+results&amp;start=1000&amp;sa=N I didn't know that until recently, because I'd never taken the time to click into the 100th page of search results on a query.

If you're actually returning more than 1,000 results back to the user, then I think there's a bigger problem at hand than the fact that the data store won't let you do it.

One possible (legitimate) reason to need that many results is if you were doing a large operation on the data and presenting a summary (for example, what is the average of all this data). The solution to this problem (which is talked about in the Google I/O talk) is to calculate the summary data on-the-fly, as it comes in, and save it.

Tony Arkles
Agreed. There's no point in returning thousands of results to a user in a single page.
Nick Johnson
And it follows from there that there's no point pulling 1000 records from the Datastore, unless you're going to return all of them to the user.
Tony Arkles
If I want to sum a property of more than 1000 entities stored in the datastore, I would need to address this limit somehow. jgeewax has the solution I was looking for.
bentford
+14  A: 

App Engine gives you a nice way of "paging" through the results by 1000 by ordering on Keys and using the last key as the next offset. They even provide some sample code here:

http://code.google.com/appengine/docs/python/datastore/queriesandindexes.html#Queries_on_Keys

Although their example spreads the queries out over many requests, you can change the page size from 20 to 1000 and query in a loop, combining the querysets. Additionally you might use itertools to link the queries without evaluating them before they're needed.

For example, to count how many rows beyond 1000:

class MyModel(db.Expando):
    @classmethod
    def count_all(cls):
        """
        Count *all* of the rows (without maxing out at 1000)
        """
        count = 0
        query = cls.all().order('__key__')

        while count % 1000 == 0:
            current_count = query.count()
            if current_count == 0:
                break

            count += current_count

            if current_count == 1000:
                last_key = query.fetch(1, 999)[0].key()
                query = query.filter('__key__ > ', last_key)

        return count
jgeewax
This will loop forever if the actual count happens to be an exact multiple of 1000 -- wrong exit condition!-) Otherwise nice...
Alex Martelli
This won't work. The while loop is never entered b/c count is initialized to zero.
dave paola
A: 

The proposed solution only works if entries are sorted by key... If you are sorting by another column first, you still have to use a limit(offset, count) clause, then the 1000 entries limitation still apply. It is the same if you use two requests : one for retrieving indexes (with conditions and sort) and another using where index in () with a subset of indexes from the first result, as the first request cannot return more than 1000 keys ? (The Google Queries on Keys section does not state clearly if we have to sort by key to remove the 1000 results limitation)

A: 

JJG: your solution above is awesome, except that it causes an infinite loop if you have 0 records. (I found this out while testing some of my reports locally).

I modified the start of the while loop to look like this:

while count % 1000 == 0:
    current_count = query.count()
    if current_count == 0:
        break
mhawthorne
+2  A: 
class Count(object):
def getCount(self,cls):
 class Count(object):
def getCount(self,cls):
 """
 Count *all* of the rows (without maxing out at 1000)
 """
 count = 0
 query = cls.all().order('__key__')


 while 1:
  current_count = query.count()
  count += current_count
  if current_count == 0:
   break

  last_key = query.fetch(1, current_count-1)[0].key()
  query = query.filter('__key__ > ', last_key)

 return count
fun_vit
A: 

I'm building an app that needs to report on events occurring. An event has a type and I also need to report by event type.

The 1000 limit is throwing a wrench into how I would normally do it. I don't need to retrieve all of the entities and present them to the user, but I do need to show the total count for a specific date range. Any suggestions?

Thanks!

Linsidious
I believe the recommendation in a non-relational database is to keep a running count as you add entities. For each event type (or whatever is the correct granularity), keep a column that always has the current total count for the date ranges you care about.
npdoty
+5  A: 

This 1K limit issue is resolved.

query = MyModel.all() for doc in query: print doc.title

By treating the Query object as an iterable: The iterator retrieves results from the datastore in small batches, allowing for the app to stop iterating on results to avoid fetching more than is needed. Iteration stops when all of the results that match the query have been retrieved. As with fetch(), the iterator interface does not cache results, so creating a new iterator from the Query object will re-execute the query.

The max batch size is 1K. And you still have the auto Datastore quotas as well.

But with the plan 1.3.1 SDK, they've introduced cursors that can be serialized and saved so that a future invocation can begin the query where it last left off at.

Tiger Woods
+11  A: 

Just for the record - fetch limit of 1000 entries is now gone:

http://googleappengine.blogspot.com/2010/02/app-engine-sdk-131-including-major.html

Quotation:

No more 1000 result limit - That's right: with addition of Cursors and the culmination of many smaller Datastore stability and performance improvements over the last few months, we're now confident enough to remove the maximum result limit altogether. Whether you're doing a fetch, iterating, or using a Cursor, there's no limits on the number of results.

Tomasz Zielinski
+7  A: 

Starting with Version 1.3.6 (released Aug-17-2010) you CAN

From the changelog:

Results of datastore count() queries and offsets for all datastore queries are no longer capped at 1000.

Shay Erlichmen
I'm still getting just only 1000 for about 3600 it should. How to implement this? Thanks
Ivan Slaughter
@Ivan a single fetch can only return 1000, but you can iterate over the query fetching 1000 at a time and setting the offset to the next 1000. I will post code for that soon.
Shay Erlichmen
A: 

we are using something in our ModelBase class that is:

@classmethod
def get_all(cls):
  q = cls.all()
  holder = q.fetch(1000)
  result = holder
  while len(holder) == 1000:
    holder = q.with_cursor(q.cursor()).fetch(1000)
    result += holder
  return result

This gets around the 1000 query limit on every model without having to think about it. I suppose a keys version would be just as easy to implement.

Gabriel