Python if statement not working as expected

Question

I'm searching for a string in a website and checking to see if the location of this string is in the expected location. I know the string starts at the 182nd character, and if I print temp it will even tell me that it is 182, however, the if statement says 182 is not 182.

Some code

f = urllib.urlopen(link)

 #store page contents in 's'
 s = f.read()
 f.close()
 temp = s.find('lettersandnumbers')

 if (htmlsize == "197"):
  #if ((s.find('lettersandnumbers')) == "182"):
  if (temp=="182"):
   print "Glorious"
   doStuff()
  else:
   print "HTML not correct.  Aborting."
 else:
  print htmlsize
  print "File size is incorrect.  Aborting."

Answer 1

Im not a python guru, but ill take a shot

Try it like this

if (temp == 182)

Why? See SilentGhost answer. It involves types

Answer 2

str.find returns integer, not string. String-integers comparison always returns False.