How to slice a list of objects in association of the object attributes

Question

I have a list of fixtures.Each fixture has a home club and a away club attribute.I want to slice the list in association of its home club and away club.The sliced list should be of homeclub items and awayclub items.

Easier way to implement this is to first slice a list of fixtures.Then make a new list of the corresponding Home Clubs and Away Clubs.I wanted to know if we can do this one step.

Answer 1

Not quite the answer you were after, but (assuming [(home1, away1), (home2, away2), ...]) this is about as simple as you'll get.

homes = [h for h,a in fixtures]
aways = [a for h,a in fixtures]

Answer 2

It's not very clear what you're trying to do, but this code will take the first five fixtures, and return a list of tuples, each of which contains a home and an away value of the respective object:

result = [(i.home, i.away) for i in fixtures[:5]]

This will separate the two into two lists:

homes = [i.home for i in fixtures[:5]]
aways = [i.away for i in fixtures[:5]]

Or on one line:

homes, aways = [i.home for i in fixtures[:5]], [i.away for i in fixtures[:5]]

Answer 3

Sure, with a bit of work:

def split(fixture):
    home, away = [], []
    for i, f in enumerate(fixture):
        if i >= 5:
            home.append(f.home)
            away.append(f.away)
    return home, away

Or:

home, away = zip(*itertools.imap(operator.attrgetter('home', 'away'),
    itertools.islice(fixture, 5, None)))