Problem of * in Command line argument

Question

I wrote a program in Java that accepts input via command line arguments. I get input of two numbers and an operator from the command line. To multiply two numbers, i have to give input as e.g. 5 3 *, but it's not working as written.

Why is it not accepting * from the command line?

Answer 1

That's because * is a shell wildcard: it has a special meaning to the shell, which expands it before passing it on to the command (in this case, java).

Since you need a literal *, you need to escape it from the shell. The exact way of escaping varies depending on your shell, but you can try:

java ProgramName 5 3 "*"

Or:

java ProgramName 5 3 \*

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By the way, if you want to know what the shell does with the *, try printing the content of String[] args to your main method. You'll find that it will contain names of the files in your directory.

This can be handy if you need to pass some filenames as command line arguments.

See also

• Wikipedia: glob

  For example, if a directory contains two files, a.log and b.log then the command cat *.log will be expanded by the shell to cat a.log b.log

• Wikipedia: Escape character

  In Bourne shell (sh), the asterisk (*) and question mark (?) characters are wildcard characters expanded via globbing. Without a preceding escape character, an * will expand to the names of all files in the working directory that don't start with a period if and only if there are such files, otherwise * remains unexpanded. So to refer to a file literally called "*", the shell must be told not to interpret it in this way, by preceding it with a backslash (\).

Answer 2

Try surrounding the * with quotes like "*". The star is a reserved symbol on the command line.

Answer 3

* has special meaning in shell interpreters. How to get a * literally is depending on what shell interpreter you are using. For Bash, you should put single quotes around the *, i.e. '*', instead of double quotes like "*".