Removing word + wildcard number from string

Question

Hi,

I have a string that is

$str = "testingSUB1";

How can I strip out SUB* from the string? I assume using preg_replace but I'm not good with matching what I want with regex.

Does anyone know how I can do this?

Thank you

Answer 1

That's the way.

$str = preg_replace("#SUB[0-9]+#", "", $str);

The #s are delimiters; they can be any non-alphanumeric/whitespace/backslash character that doesn't appear in the pattern. [0-9] means any digit (you can use \d too in some languages, but I usually don't bother), and the + means one or more of the previous, so if you take the + out it will only replace the first digit

Answer 2

This should do it:

$word = 'SUB';
$string = 'testingSUB1';

echo preg_replace('~^(.*?)(' . preg_quote($word, '~') . '\d+)(.*?)$~', '$1$2', $string);

EDIT - This is better:

echo preg_replace('~' . preg_quote($word, '~') . '\d+~', '', $string);