regex to get current page or directory name?

Question

I am trying to get the page or last directory name from a url

for example if the url is: http://www.example.com/dir/ i want it to return dir or if the passed url is http://www.example.com/page.php I want it to return page Notice I do not want the trailing slash or file extension.

I tried this:

$regex = "/.*\.(com|gov|org|net|mil|edu)/([a-z_\-]+).*/i";

$name = strtolower(preg_replace($regex,"$2",$url));

I ran this regex in PHP and it returned nothing. (however I tested the same regex in ActionScript and it worked!)

So what am I doing wrong here, how do I get what I want?

Thanks!!!

Answer 1

Don't use / as the regex delimiter if it also contains slashes. Try this:

$regex = "#^.*\.(com|gov|org|net|mil|edu)/([a-z_\-]+).*$#i";

Answer 2

You may try tho escape the "/" in the middle. That simply closes your regex. So this may work:

$regex = "/.*\.(com|gov|org|net|mil|edu)\/([a-z_\-]+).*/i";

You may also make the regex somewhat more general, but that's another problem.

Answer 3

You can use this

array_pop(explode('/', $url));

Then apply a simple regex to remove any file extension

Answer 4

As much as I personally love using regular expressions, more 'crude' (for want of a better word) string functions might be a good alternative for you. The snippet below uses sscanf to parse the path part of the URL for the first bunch of letters.

$url  = "http://www.example.com/page.php";
$path = parse_url($url, PHP_URL_PATH);
sscanf($path, '/%[a-z]', $part);
// $part = "page";

Answer 5

This expression:

(?<=^[^:]+://[^.]+(?:\.[^.]+)*/)[^/]*(?=\.[^.]+$|/$)

Gives the following results:

http://www.example.com/dir/            dir
http://www.example.com/foo/dir/        dir
http://www.example.com/page.php        page
http://www.example.com/foo/page.php    page

Apologies in advance if this is not valid PHP regex - I tested it using RegexBuddy.

Answer 6

Save yourself the regular expression and make PHP's other functions feel more loved.

$url  = "http://www.example.com/page.php";
$filename = pathinfo(parse_url($url, PHP_URL_PATH), PATHINFO_FILENAME);

Warning: for PHP 5.2 and up.