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41

answers:

1

I am trying to migrate a legacy mailing list to a new web forum software and was wondering if mailman has an export option or an API to get all lists, owners, members and membership types.

A: 

probably too late, but the list_members LISTNAME command (executed from a shell) will give you all the members of a list.

list_admins LISTNAME will give you the owners What do you mean by membership type? list_members does have an option to filter on digest vs non-digest members. I don't think there's a way to get the moderation flag without writing a script for use with withlist