Warning: sprintf() [function.sprintf]: Too few arguments in /home/inrunitc/public_html/chek/chek.php on line 132
Query was empty
I am new to PHP and mysql and I have like 88 fields in my form - what should I do ?
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314answers:
1
+1
A:
This happens if you have something like
$s = sprintf('%d %d %d', 4);
There are three placeholders in the format string but only one parameter.
VolkerK
2010-05-03 17:47:04
what if you had this: $s = sprintf('%d %d', 4, 2, 1); Would this replace the two digit spaces and ignore the third supplied number (1) or throw an error.
Ashley Ward
2010-09-22 12:18:16
@Ashley: No error/warning/notice message with the vanilla php.net 5.3.3 build, but there may be other (patched/hardened) builds that raise e.g. a notice.
VolkerK
2010-09-22 20:47:17