hi ,,,,,
I have a problem in the following code ...
The following code works as follows displays the invites for each member so that if he had five invite from supposed to be displayed all on one page
But before you code that does not function Proper image is the only display one invite on the page and until the approval or rejection of the invitation displays the invite the other ....
But this is not my want to offer all on one page
I wish I could solve the problem and I can view all calls in one page
I think that the problem is in the order code
I think that the problem is in the order code
my code :
<?php
session_start();
if (!isset($_SESSION['user_id']))
{
header("Location: login.php");
}
$id=$_SESSION['user_id'];
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<center>
<?php
include("connect.php");
$sql =mysql_query("select * from ninvite where recieverMemberID ='$id' and viwed= '0'");
$num =mysql_num_rows($sql);
echo $num ;
if ($num>0)
{
while($row=mysql_fetch_array($sql))
{
$sender=$row['SenderMemberID'];
$room=$row['RoomID'];
$sql =mysql_query("select MemberName from members where MemberID ='$sender' ");
$sql1 =mysql_query("select RoomName from rooms where RoomID ='$room' ");
while($row=mysql_fetch_array($sql))
{$mem =$row['MemberName'];
}
while($rows=mysql_fetch_array($sql1))
{ $Ro =$rows['RoomName'];
?>
<form action="join.php" method="post">
<label>
</label> <br/>
<label> <?php echo " you have invite from $mem to join $Ro"; ?> </label>
<br/><br/>
<label>accept</label>
<input name="radio1" type="radio" value="accpet" />
<label>reject</label>
<input name="radio1" type="radio" value="Reject" /><br/>
<input type="submit" name="submit" value="done" />
</form>
<?php } } } ?>
</center>
</body>
</html>
thanks alot.