tags:

views:

33

answers:

1

What I want is to put a custom button in each row of a page of the admin listing.
These buttons will have a function associate to it acting over that line.
I've already knew the "admin actions", but it's not what I want, ok?

Thank you!

+2  A: 

You can declare in your ModelAdmin a function to generate the html for your button, e.g.

    def button(self, obj):
        return mark_safe('<input type="...">')
    title.short_description = 'Action'
    title.allow_tags = True

And then put it in your in your list_display-tuple.

class MyAdmin(admin.ModelAdmin)
    list_display=('name', 'button')

http://docs.djangoproject.com/en/dev/ref/contrib/admin/#modeladmin-options

lazerscience
Thank you!Sorry for being late to see the answer, i've found another way to solve my problem. Anyway, it could help ^^
Jayme