That's the question. Why would I use implicit_value over default_value and vice versa?
Thanks!
That's the question. Why would I use implicit_value over default_value and vice versa?
Thanks!
If I remember right, the difference arises with an option that allows something like -X=Y
(where "Y" might be, for example, a number). The default value is what you get if the user hasn't entered a -X
on the command line. An implicit value is is what you get if the user enters -X
on the command line without specifying a value.
Consider, for example, gcc, which supports optimization levels from 0 to 3 (IIRC). If you don't specify -O
at all, it defaults to -O0
(i.e., optimization is turned off). If you specify -O
(with no number) you get the implicit value, equivalent to -O1
. You can also specify -O1
explicitly, or you can specify -O2
or -O3
.
deafult_value()
is the value that will be put in the variables_map
if the user didn't specify another value:
./a.out # implies width=75 if that's the default_value for width
./a.out --width=80 # default_value not used
implicit_value()
is the value that will be used if the user specifies the option but without an adjacent value.
./a.out --width # implies width=75 if that's the implicit_value for width
./a.out --width=80 # implicit value not used
If you use implicit_value
then in commandline options's short options the user must specify the value immediately after the option:
./a.out -w80 # implicit_value not used
./a.out -w 80 # wrong: 80 parsed as extra arg if implicit_value is defined