Delete XML node based on position in Java

Question

I have an XML file like this:

<A>
  <B>
    <c>1<c/>
    <d>2<d/>
    <e>3<e/>
  </B>
  <B>
    <c>11<c/>
    <d>22<d/>
    <e>33<e/>
  </B>
</A>

Say I wanted to delete the second node. How would I do this?

I have not written code to do this yet. I've researched online but was not able to find just what I'm looking to do. My program lists the items in a jtable and it needs to let you select the item and hit a delete button.

I've implemented everything except the deletion, but there is too much and nothing really relevant.

Answer 1

You can find it with the XPath expression /A/B[2].

XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression compiledExp = xPath.compile("/A/B[2]");
Node foundNode = (Node)compiledExp.evaluate(doc, XPathConstants.NODE);

then use:

foundNode.getParentNode().removeChild(foundNode);

to delete it