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Answer 1

+9 A:

Like this: $('.smallBlock').load('targetUnderSameDomain.php .anotherSmallBlock');

In the first part you select the block where you want to insert the block of the targeted file. The load function has two parts: The first part is where you select the targeted file, the second is optional, but there you can select an element within the targeted file's html.

Hope your accept rate will grow through this answer ;)

Nort 2010-05-16 12:06:17

Answer 2

+2 A:

you can use the load command. For a simple page like this:

<html>
<head>
   <title>test</title
</head>
<body>
   <div id="content"> </div>
</body>
</html>

you could fill the Div with id = content like this:

$('#content').load('yourUrl.php');

Hope this helps you and be sure to accept if it does ;)

EDIT: changed from get() to load()

the syntax for the get command would be:

$.get('yourUrl.php', function(data){
   $('#content').html(data);
 });

Falle1234 2010-05-16 12:06:48

[`.get()`](http://api.jquery.com/get/) is a different function, you want [`.load()`](http://api.jquery.com/load/) here :)

Nick Craver 2010-05-16 12:10:08

yeah your right... guess my brain doesn't work that well on a sunday ;)

Falle1234 2010-05-16 12:12:16

y cant we use .get() over here...that will also fetch data rite ?... can i pass parameters to .load() function?

pradeep 2010-05-17 05:14:11

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Loading a page using jQuery.

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