How to call a script that expects $_POST from inside a function

Question

My script.php accepts $_POST input and echos a string.

$theinput = $_POST['theinput'];
$output = //some processing;
echo $output;

I need the same code in another function in a different file second.php and don't want to repeat the code. But the first script script.php expects input as $_POST. My input in the function is not $_POST just a regular parameter.

function processinput($someinput){
   //run the same script above, 
   //just the input is a parameter, not a `$_POST`
}

Any ideas how to do that? Is it possible to simulate a $_POST or something like that?

Answer 1

function processinput($someinput){ 
   //I need to call the above script and give it  
   //the same input `$someinput` which is not a `$_POST` anymore 
   $results = strrev($someinput);
   return $results;
} 

$theinput = $_POST['theinput'];
$output = processinput($theinput);
echo $output; 

Answer 2

Are you looking for the include or include_once method?

second.php:

function processinput($someinput){
  $output = //some processing;
  echo $output;
}

script.php:

include_once('second.php'); // second.php contains processinput()
$theinput = $_POST['theinput'];
processinput($theinput);

Answer 3

you can always assign values to $_POST just as if it is an array. A bit of a hack-job, and you are probably better off changing the function to take the value in as a parameter, but it will work.

$_POST['theinput'] = "value";