why is this dictionary line number count not working?

Question

i have this piece of code the last bit of the code starting from d = {} im trying to print the words with its line number located in the text but it is not working its only printing the words anyone know why ??? need help ASAP

import sys
import string

text = []
infile = open(sys.argv[1], 'r').read()
for punct in string.punctuation:
    infile = infile.replace(punct, "")
    text = infile.split("\n")

dict = open(sys.argv[2], 'r').read()
dictset = []
dictset = dict.split()

words = []
words = list(set(text) - set(dictset))
words = [text.lower() for text in words]
words.sort()

d = {}
counter = 0
for lines in text:
    counter += 1
if word not in d:
    d[words] = [counter]
else:
    d[words.append[counter]
print(word, d)

this code outputs:

helo
goin
ist

i want it to output :

helo #tab# 3   4 
goin #tab# 1   2

Answer 1

text is a list of WORDS, it's not a list of LINES. When you do:

text = infile.split()

you're irreversibly, forever throwing away all connections between a word and the line it was in. So when you later write

for lines in text:

it's a lie: text's items are words, not lines. If they weren't, then this other earlier line:

 words = list(set(text) - set(dictset))

would be totally broken -- this depends on text's items being words, not lines.

And, by the way, when you do:

  words = [text.lower() for text in words]

text is now left bound to the last item in words -- you've destroyed whatever other value it had previously.

Recommendation number one: stop reusing identifiers for many different, incompatible purposes. Make a commitment to yourself that no identifier shall ever be bound to two different things within any one of your programs. This will, at least, reduce the incredible amount of utter confusion that you manager to pile onto so few lines.