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views:

77

answers:

1

I needed to know what was in my Ruby load path, so I did this:

$ ruby -e "puts $LOAD_PATH"

It didn't print anything out, which I didn't expect. So I tried this:

$ ruby -e "puts $:"
/usr/local/lib/site_ruby/1.8
/usr/local/lib/site_ruby/1.8/i486-linux
/usr/local/lib/site_ruby/1.8/i386-linux
/usr/local/lib/site_ruby
/usr/lib/ruby/vendor_ruby/1.8
/usr/lib/ruby/vendor_ruby/1.8/i486-linux
/usr/lib/ruby/vendor_ruby
/usr/lib/ruby/1.8
/usr/lib/ruby/1.8/i486-linux
/usr/lib/ruby/1.8/i386-linux
.

Why does the second one give me the expected output and the first one doesn't? Shouldn't they be the same? I just tried it in irb, and I got the results I expected.

This is my Ruby version, in case it makes a difference:

$ ruby --version
ruby 1.8.7 (2008-08-11 patchlevel 72) [i486-linux]
+3  A: 

They are not. Try running this command:

$ ruby -e 'puts $LOAD_PATH'

which doesn't make shell expand $LOAD_PATH due to use of ' instead of ".

Pavel Shved
Gah! That makes perfect sense. I guess this is the first time I've used a global when doing `ruby -e`. :)
Benjamin Oakes