I want to check if a page returns the status code 401. Is this possible?
Here is my try, but it only returns 0.
$.ajax({
url: "http://my-ip/test/test.php",
data: {},
complete: function(xhr, statusText){
alert(xhr.status);
}
});
views:
187answers:
3
+1
A:
Use the error callback.
For example:
jQuery.ajax({'url': '/this_is_not_found', data: {}, error: function(xhr, status) {
alert(xhr.status); }
});
Will alert 404
baloo
2010-06-02 08:17:06
indeed it did. I'm kinda new to jQuery. But what about 401 status? How do i save the status to a variable? o_O
cvack
2010-06-02 08:46:25
Firebug returns this: GET http://my-ip/test/test.php 401 Authorization Required
cvack
2010-06-02 08:48:39
It will show 401 the same way.What exactly do you want to do with the error?
baloo
2010-06-02 08:55:46
If 401 dont send user to this page. The error only alerts if the page is not found (404)
cvack
2010-06-02 09:05:24
Tested this in Firefox where it catched 401 as well, perhaps this is not true for all browsers
baloo
2010-06-02 09:13:50
A:
I think you should also implement the error function of the $.ajax method.
error(XMLHttpRequest, textStatus, errorThrown)Function
A function to be called if the request fails. The function is passed three arguments: The XMLHttpRequest object, a string describing the type of error that occurred and an optional exception object, if one occurred. Possible values for the second argument (besides null) are "timeout", "error", "notmodified" and "parsererror".
$.ajax({
url: "http://my-ip/test/test.php",
data: {},
complete: function(xhr, statusText){
alert(xhr.status);
}
error: function(xhr, statusText, err){
alert("Error:" + xhr.status);
}
});
GvS
2010-06-02 08:17:42
A:
$.ajax({
url: "http://my-ip/test/test.php",
data: {},
error: function(xhr, statusText, errorThrown){alert(xhr.status);}
});
vartec
2010-06-02 08:19:39