Hi
How do I do a check in python that a date appears in the last year. i.e. date between now and (now-1 year)
Thanks
+2
A:
In [10]: today=datetime.date.today()
In [11]: datetime.date(2010,5,5) < today
Out[11]: True
In [12]: today-datetime.timedelta(days=365) <= datetime.date(2010,5,5) < today
Out[12]: True
In [13]: today-datetime.timedelta(days=365) <= datetime.date(2009,5,5) < today
Out[13]: False
Edit: if today is the leap year 2000-2-29, then today-datetime.timedelta(days=365) is 1999-3-1. If you'd like one year ago to be 1999-2-28 then you could use
def add_years(date,num):
try:
result=datetime.date(date.year+num,date.month,date.day)
except ValueError:
result=datetime.date(date.year+num,date.month,date.day-1)
return result
today=datetime.date(2000,2,29)
print(add_years(today,-1))
# 1999-02-28
unutbu
2010-06-04 09:08:28
can i put datetime.timedelta(year=1) as some years will be 366 days with the leap year
John
2010-06-04 09:13:51
@John: No you can't, read the documentation. The signature is *datetime.timedelta([days[, seconds[, microseconds[, milliseconds[, minutes[, hours[, weeks]]]]]]])* Does one day matter that much?
Felix Kling
2010-06-04 09:15:19
yes if i want it one year from now.
John
2010-06-04 09:16:54
+2
A:
This should work for leap years:
>>> from datetime import date
>>> today = date.today()
>>> date(today.year - 1, today.month, today.day) < date(2009, 06, 05) <= today
True
>>> date(today.year - 1, today.month, today.day) < date(2009, 06, 04) <= today
False
>>> date(today.year - 1, today.month, today.day) < date(2010, 07, 04) <= today
False
fmark
2010-06-04 09:14:50