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+2 A:

$regex = '#^.*?(hate).*$#ims';
$str = preg_replace($regex, '', $str);

To add more "bad words", just add them in the ():

$regex = '#^.*?(hate|anotherbadword|yetanother|etc).*$#ims';

The leading ^ and trailing $ match the full string. The i option is for case insensitive matching. The m enables multi-line mode (so that ^ and $ match the whole string, as opposed to a single line in it). The s enables DOTALL (so the . matches new line characters as well).

You could

ircmaxell 2010-06-04 19:57:26

as an alternative you can store all the words you don't want in an array and iterate them. `$bad = array(...); for ($i = 0; $i < count($bad) $i++) { $str = preg_replace('#^.*?(' . $bad[$i] . ').*$#ims', '', $str); }` (far more readable on multiple lines but it doesn't qualify as a separate answer as that'd be stealing :)

Matt S 2010-06-04 20:00:05

@Matt S: IF you were going to use a loop, I'd use `stripos()`... Something like `foreach($bad as $word) { if (stripos($string, $word) !== false) { $string = ''; break;} }`. The break is so that once you kill the string, you don't continue the loop. Or you could build the regex from the loop: `$regex = '#^.*?('; foreach ($bad as $word) { $regex .= preg_quote($word, '#') . '|'; } $regex = rtrim($regex, '|') . ').*$#ims';`...

ircmaxell 2010-06-04 20:07:13

Correct, personally I dislike the use of breaks in my statements which is why I used the `for ()` instead of the `foreach ()`. You of course are correct on the `stripos` being a better choice than a regex.

Matt S 2010-06-05 15:31:31

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