Create a GUID in Java

+6 A:

Have a look at the UUID class. For example:

If you want a random UUID you can use the randomUUID method.
If you want a UUID initialized to a specific value you can use the UUID constructor or the fromString method.

Mark Byers 2010-06-06 01:14:45

+2 A:

java.util.UUID.randomUUID();

Kaleb Brasee 2010-06-06 01:16:03

+3 A:

This stackoverflow question discusses and link the topic in depth.

Daniel Ribeiro 2010-06-06 01:17:10

I'm still getting used to forum protocol. How relevant is it that anyone who doesn't know that Java refers to GUIDs as UUIDs would have a lot of trouble finding that question and likely post again if this one is closed out? (The question refers to UUIDs and is only tagged with UUID)

DutrowLLC 2010-06-07 15:15:05

Not sure I understand what you mean, but there is a closing vote for duplicate questions on StackOverflow. However, it requires a lot of reputation for voting, and I usually find its usage should be taken with a grain of salt. In the end, having more of the same question, even closed ones, is more benefical than having it answered only once.

Daniel Ribeiro 2010-06-07 17:33:33

+3 A:

It depends what kind of UUID you want.

The standard Java UUID class generates type 3 and 4 UUIDs.
The Java UUID Generator (JUG) implementation purports to support "all 3 'official' types of UUID as defined by RFC-4122" ... though the RFC actually defines 4 types and mentions a 5th type.

For more information on UUID types and variants, there is a good summary in Wikipedia, and the gory details are in the RFCs and other specifications.

Stephen C 2010-06-06 03:28:17

ansaurus

tags:

views:

answers:

Create a GUID in Java

related questions