Scroll to a position in a listView

Question

Hi,

I have a long listView that the user scrolls around and then returns to the previous menu . What I want is that when the user opens this list View again the list to be scrolled to where the it was previously left. Any ideas on how this can be achieved ?

Answer 1

A very simple way:

/** Save the position **/
int currentPosition = listView.getFirstVisiblePosition();

//Here u should save the currentPosition anywhere

/** Restore the previus saved position **/
listView.setSelection(savedPosition);

The method setSelection will reset the list to the supplied item. If not in touch mode the item will actually be selected if in touch mode the item will only be positioned on screen.

A more complicated approach:

listView.setOnScrollListener(this);
//Implements the interface:
@Override
    public void onScroll(AbsListView view, int firstVisibleItem,
            int visibleItemCount, int totalItemCount) {
        mCurrentX = view.getScrollX();
        mCurrentY = view.getScrollY();
    }

    @Override
    public void onScrollStateChanged(AbsListView view, int scrollState) {}



//Save anywere the x and the y

/** Restore: **/
listView.scrollTo(savedX, savedY);

Answer 2

Try this:

// save index and top position
int index = mList.getFirstVisiblePosition();
View v = mList.getChildAt(0);
int top = (v == null) ? 0 : v.getTop();

// ...

// restore
mList.setSelectionFromTop(index, top);