The answer to your question partially lies in a previous questions on SO:
http://stackoverflow.com/questions/779414/java-generics-pairstring-string-stored-in-hashmap-not-retrieving-key-value-pr
import java.lang.*;
import java.util.*;
public class Pair<TYPEA, TYPEB> implements Comparable< Pair<TYPEA, TYPEB> > {
protected final TYPEA Key_;
protected final TYPEB Value_;
public Pair(TYPEA key, TYPEB value) {
Key_ = key;
Value_ = value;
}
public TYPEA getKey() {
return Key_;
}
public TYPEB getValue() {
return Value_;
}
public String toString() {
System.out.println("in toString()");
StringBuffer buff = new StringBuffer();
buff.append("Key: ");
buff.append(Key_);
buff.append("\tValue: ");
buff.append(Value_);
return(buff.toString() );
}
public int compareTo( Pair<TYPEA, TYPEB> p1 ) {
System.out.println("in compareTo()");
if ( null != p1 ) {
if ( p1.equals(this) ) {
return 0;
} else if ( p1.hashCode() > this.hashCode() ) {
return 1;
} else if ( p1.hashCode() < this.hashCode() ) {
return -1;
}
}
return(-1);
}
public int hashCode() {
int hashCode = Key_.hashCode() + (31 * Value_.hashCode());
System.out.println("in hashCode() [" + Integer.toString(hashCode) + "]");
return(hashCode);
}
@Override
public boolean equals(Object o) {
System.out.println("in equals()");
if (o instanceof Pair) {
Pair<?, ?> p1 = (Pair<?, ?>) o;
if ( p1.Key_.equals( this.Key_ ) && p1.Value_.equals( this.Value_ ) ) {
return(true);
}
}
return(false);
}
public static void main(String [] args) {
HashMap< Pair<String, int>, String> table = new HashMap<Pair<String,int>, String>();
table.put(new Pair<String, int>("a", 1), "x");
table.put(new Pair<String, int>("a", 2), "y");
table.put(new Pair<String, int>("a", 3), "z");
table.put(new Pair<String, int>("b", 1), "h");
table.put(new Pair<String, int>("b", 2), "l");
table.put(new Pair<String, int>("b", 3), "m");
table.put(new Pair<String, int>("c", 1), "o");
table.put(new Pair<String, int>("c", 2), "a");
table.put(new Pair<String, int>("c", 3), "k");
String val = table.get(new Pair<String, int>("a", 1)); //val is x for this input pair
}
}