What happens when there is var-arg hierarchy tie while performing method overloading?

Question

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SCJP question: Java method overloading with var-args. What is the rationale?

Class Vararg{
      static void go(Integer... i){
           System.out.println("Wrapper Class");
      }
      static void go(int... i){
           System.out.println("Primitive Type");
      }
      public static void main(String[] args){
         int i =5;
         Vararg.go(i);
      }
}

Why does the above code doesn't compile? I know there is a vararg hierarchy tie. But why compiler is not able to resolve this kindof tie and execute the above code?