PHP list of specific files in a directory

Question

The following code will list all the file in a directy

<?php
    if ($handle = opendir('.')) {
    while (false !== ($file = readdir($handle)))
    {
        if ($file != "." && $file != "..")
        {
            $thelist .= '<LI><a href="'.$file.'">'.$file.'</a>';
        }
    }
    closedir($handle);
    }
?>

<P>List of files:</p>
<UL>
<P><?=$thelist?></p>
</UL>

While this is very simple code it does it job.

I'm now looking for a way to list ONLY file that have .xml (or .XML) at the end, how do I do that?

Code is appreciate, thanks!

jess

Answer 1

You'll be wanting to use glob()

http://uk2.php.net/glob

Example:

$files = glob('/path/to/dir/*.xml');

Answer 2

$it = new RegexIterator(new DirectoryIterator("."), "/\\.xml\$/i"));

foreach ($it as $filename) {
    //...
}

You can also use the recursive variants of the iterators to traverse an entire directory hierarchy.

Answer 3

In PHP5, you can just use scandir() to get the list of files in a directory as an array. Then just filter it for .xml files.

Here’s a helper function:

function file_list($d, $x){ 
 foreach(array_diff(scandir($d), array('.', '..')) as $f) if (is_file($d . '/' . $f) && (($x) ? ereg($x . '$' , $f) : 1)) $l[] = $f;
 return $l; 
}

// Use as follows
$files = file_list('/var/www/html/dir', '.xml');

Answer 4

Simplest answer is to put another condition '.xml' == strtolower(substr($file, -3)).

But I'd recommend using glob instead too.

Answer 5

if ($handle = opendir('.')) {
    while (false !== ($file = readdir($handle)))
    {
        if ($file != "." && $file != ".." && strtolower(substr($file, strrpos($file, '.') + 1)) == 'xml')
        {
            $thelist .= '<LI><a href="'.$file.'">'.$file.'</a>';
        }
    }
    closedir($handle);
}

A simple way to look at the extension using substr and strrpos