Pass Two Values to a View

Question

OK, I'm pretty sure I know the answer to this but just in case.

I know I can pass in a composite class to a view / partial view. My question though is can I pass in an object without first having a model.

So something like Html.RenderPartial("MyPartialView", new { id=10, name="slappy" });

If I can, what would the partial view look like?

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<?????>" %>

and how would I access the properties?

Model.id???

EDIT

Just a follow up based on @Graphain's solution this is in my view;

<% Html.RenderPartial("PagedList", new { id="10" } ); %>

Within my Partial View I have this;

[<%= ViewData["id"] %>] which renders [];

However this;

<%= Html.TextBox("id") %>

Gives me a textbox with the number 10 in it.

Answer 1

Sure.

Your partial view declaration should look like this:

 <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl" %> 

And you'll access properties like this:

 <%=ViewData.Eval("id")%>

You'll be using ViewUserControl rather than ViewUserControl(Of TModel).

This means you'll be accessing a ViewDataDictionary rather than a ViewDataDictionary(Of TModel) and will be dealing with just regular object data rather than strongly typed data (as well as string keys rather than strong-typed property names).

This link is a good intro on the differences:

The first type of ViewDataDictionary is an untyped collection consisting of a string and an object. The string represents the key, and the object holds the actual data. Like any untyped collection, the object can be of any type, but must be cast to the correct type before it is used. Items are referenced via their key in the ViewData property of the ViewUserControl (in the case of a PartialView). The second is a strongly typed collection, where items are properties of the ViewUserControl.Model property.

Answer 2

I don't think you can use an Anonymous class as ViewData.

Answer 3

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<ExpandoObject>" %>

In your controller:

var model = new ExpandoObject();
model.id = 1;
model.name = "John";
model.DynamicAttrs = "anything dynamic";

Maybe you are confused that why don't we use:

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<dynamic>" %>

which theoretically gives a Model whose type is dynamic. But here we can't because dynamic types are generated as "internal" that you can't visit it in the View. So we use ExpandoObject instead.