How can I post data using ajax and display the posted data in a div on the same page without page refresh??
A:
best jquery form plugin http://jquery.malsup.com/form/ even possible uploading files - ajaxed
vertazzar
2010-06-25 13:13:40
A:
Try markup something like this...
<form action="http://google.co.uk/search" method="get" onsubmit="postTheForm(this); return false;">
<input type="hidden" name="q" value="Stackoverflow"/>
<input type="submit" value="Click here"/>
</form>
<div id="postResults"></div>
With script like this...
function postTheForm(theForm){
$.post(
theForm.action,
$(theForm).serializeArray(),
function(data, textStatus, xmlHttpRequest){
$("#postResults").html(data);
}
);
}
This example uses the GET method, but this is only because Google doesn't accept POST - but the principple should get you working and then you can change to a POST (Assuming that a POST is appropriate in your case)
belugabob
2010-06-25 13:28:42
+5
A:
To do this, you should not submit the form, but capture the form data with a click event, submit the data via AJAX and as the last thing... enter the data into the DIV
element. E.g.
jQuery
$("#submitdata").click(function() {
var FormVal={ datafield1:$('#field1').val(),
datafield2:$('#field2').val()};
$.ajax({
type: "POST",
url: "myupdatepage.cfm",
dataType: "json",
data: FormVal,
async: false,
success: function(response) {
$('#fillmein').html($('#field1').val()+'<br />'+$('#field1').val()); // Assign the values to the DIV
}
});
});
HTML
<form action="">
<input type="text" id="field1">
<input type="text" id="field2">
<input type="button" id="submitdata" value="Submit data" />
</form>
<div id="fillmein"></div>
Gert G
2010-06-25 13:32:06