How to get a list of files that match some pattern?

Question

How to get a list of files that match some pattern if filenames may contain \n character?

Update: I want solution in pure vimscript, so that it will depend on nothing but vim.

Update2:

Expected output of glob function

Consider the following script:

:!touch /test ; mkdir /test$'\n' ; touch /test$'\n'/test
:echo glob('/**/test')
/test
/test
/test

That is the output of glob function. I want it be the following:

:echo NewGlob('/**/test')
['/test', '/test
/test']

Answer 1

Try this python program. It will match files like abc\n1, abc\n2abc etc.

#!/usr/bin/env python
import os, re
dirlist = os.listdir('.')
pattern = 'abc\n\\d'
for fname in dirlist:
  if re.search(pattern, fname):
    print fname.replace('\n', '\\n')

It will replace line end ('\n') characters with "\n" string for clarity.

Answer 2

you may try using ls with -b option. check the man page

Answer 3

:echo split( glob("pattern", '.'), "\r")

If you want the pattern to match files containing \n exclusively, use "*\n*".

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EDIT:

I see, the character you use in the filename is the same as the one used by glob() to distinguish results. As a consequence, we can't rely of glob(). ghostdog74 gave a good answer then:

:echo split( system('ls -1bd test*'), "\n")  

Of course, this is not portable. But I do not really call this the general case -- I never see this kind of names. If glob() cannot handle this general case, then glob() must be fixed.

May be you can try with embedded python or ruby as arnold suggested. But that isn't portable either.