[python] Passing all arguments of a function to another function

Question

I want to pass all the arguments passed to a function(func1) as arguments to another function(func2) inside func1 This can be done with *args, *kwargs in the called func1 and passing them down to func2, but is there another way,

Orignially

def func1(*args, **kwargs):
    func2(*args, **kwargs)

but if my func1 signature is

def func1(a=1, b=2, c=3):

how do I send them all to func2, without using

def func1(a=1, b=2, c=3):
    func2(a, b, c)

Is there a way as in javascript callee.arguments

Answer 1

Explicit is better than implicit but if you really don't want to type a few characters:

def func1(a=1, b=2, c=3):
    func2(**locals())

locals() are all local variables, so you can't set any extra vars before calling func2 or they will get passed too.

Answer 2

Provided that the arguments to func1 are only keyword arguments, you could do this:

def func1(a=1, b=2, c=3):
    func2(**locals())