python: how to find \r\n\r\n in one single search

Question

I have to split the file content based on first occurrence of \r\n\r\n

I need flexibility such a way that the lines can just ends with \r\n\r\n or \n\n.

How to split the text?

Example added:

\===================FILE BEGIN========================================== name: about

title: About

publish: True

order: -1

\r\n

\r\n

example.com is a example website provides the latest examples in organized way.

Blah blah blah.... Blah blah blah.... Blah blah blah.... \===================File END==========================================

First portion is my header(in yaml format) used for file identity and second portion is markdown text.

Answer 1

import re

linend = re.compile(r'\r\n\r\n|\n\n')
s = 'an example\n\nstring\n\nhere'
print linend.split(s, 1)
s = 'another\r\n\r\nexample\r\n\r\nhere'
print linend.split(s, 1)

prints:

['an example', 'string\n\nhere']
['another', 'example\r\n\r\nhere']

as requested.

Answer 2

The regex pattern "\r\n\r\n|\n\n" should work. Simply use re.split or Regex.split and set maxsplit=1.