I'm using Hibernate JPA.
Suppose I have these classes:
AbstractPerson
|--> ConcreteEmployee
|--> ConcreteCustomer
Is there any way to make the concrete classes have independent IDs?
I'm using InheritanceType.TABLE_PER_CLASS.
I'm using Hibernate JPA.
Suppose I have these classes:
AbstractPerson
|--> ConcreteEmployee
|--> ConcreteCustomer
Is there any way to make the concrete classes have independent IDs?
I'm using InheritanceType.TABLE_PER_CLASS.
From the Hibernate Annotations Reference Guide:
2.2.4.1. Table per class
This strategy has many drawbacks (esp. with polymorphic queries and associations) explained in the JPA spec, the Hibernate reference documentation, Hibernate in Action, and many other places. Hibernate work around most of them implementing this strategy using
SQL UNION
queries. It is commonly used for the top level of an inheritance hierarchy:@Entity @Inheritance(strategy = InheritanceType.TABLE_PER_CLASS) public class Flight implements Serializable { ... }
This strategy supports one-to-many associations provided that they are bidirectional. This strategy does not support the
IDENTITY
generator strategy: the id has to be shared across several tables. Consequently, when using this strategy, you should not useAUTO
norIDENTITY
.
So I'm afraid what you want is not supported (and I suggest to use GenerationType.TABLE
).