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views:

83

answers:

5

Can an MD5-hash begin with a zero? What about SHA-1?

+4  A: 

MD5 hash of "a" = 0cc175b9c0f1b6a831c399e269772661

SHA1 hash of "9" = 0ade7c2cf97f75d009975f4d720d1fa6c19f4897

Neb
+4  A: 

Of course. Or two zeros. Or more. In general, the probability of a "random" input hashing to a result with k leading zero nybbles is about 2**(-4k).

GregS
+3  A: 

md5 of a = 0cc175b9c0f1b6a831c399e269772661

<?php echo md5( 'a' ); ?>

Sha1 of i = 042dc4512fa3d391c5170cf3aa61e6a638f84342

<?php echo sha1( 'i' ); ?>

why not :D

ahmet2106
+5  A: 

Yes:

$ echo -n "363" | md5sum
00411460f7c92d2124a67ea0f4cb5f85  -
$ echo -n "351" | sha1sum
0026476a20bfbd08714155bb66f0b4feb2d25c1c

Found by running the following in bash:

for i in  {1..1000} ; do echo $(echo -n $i | md5sum) $i ; done | sort | head
Joey Adams
+1  A: 

In a cryptographic hash, any given bit should be equally likely to be a 0 or a 1 for random inputs.

Chris
But aren't there sometimes specific output formats associated with a hash algorithm? E.g. DES extended format starts and ends with an underscore.
Lèse majesté
Sure, but that's not part of the hash itself, it's just markup.
Chris