check in a string php

Question

I have a string and it can contain values like this $string = '1,2,3,4,5'; I wanna put a check that will see if the string contains 4 or 5 if it contains 4 or 5 then I want to echo success otherwise if it contains 9 or 10 I wanna echo fail

I know there is a n in_array function but not sure how to use it thanks

Answer 1

in_array won't help you here because you have a string, not an array. What you're looking for is the strpos() function:

http://php.net/manual/en/function.strpos.php

Note that if it doesn't find what it's looking for in your string, it'll return false on its own, so all you have to do is check whether it returns a result or not to meet your conditions.

Answer 2

you can use strpos() to check for the existence of a substring inside a string, like this:

if(strpos(','.$string.',', ','.$number_to_check_for.',') !== false) {
    //success, substring was found
} else {
    //error, substring was not found.
}

or you could explode it into an array then use in_array():

$array = explode(',',$string);

if(in_array($number_to_check_for, $array)) {
    //success substring found
} else {
    //error, substring not found
}

But I would recommend the first solution, as it is cleaner and more efficient.

Answer 3

You can test for the number 4 like this:

if(in_array('4', explode(',', $string))) echo "it's in there";

or just by string searching:

if(strpos(',4,', ','.$string.',') !== false) echo "it's in there";

Answer 4

$set = array (1,2,3...,n); //you can use range() function if the numbers going one by one or explode if you have a string
if(in_array($var,$set))
{
   Echo 'IS in ARRAY!';
} else {
   Echo 'fail';
}

Answer 5

$goodString = '1,2,3,4,5';
$badString = '1,2,3,7,8,9,10';

function checkString($str) {
    $arr = explode(',', $str);
    $message = 'no message';
    if (
        in_array(4, $arr)||
        in_array(5, $arr)
    ) {
        $message = 'success';
    } else if (
        in_array(9, $arr)||
        in_array(10, $arr)
    ) {
        $message = 'fail';
    }
    echo $message;
}

checkString($goodString); // prints success
checkString($badString); // prints fail

Answer 6

Check all at once :)

if(in_array(array(4,5), explode(',', $string))) echo "success";

if(in_array(array(9,10), explode(',', $string))) echo "failure";