How to work with $stdout

Question

filename = "#{k}""/kabab" 
extension = ".txt" 

for i in 1..10 
  $stdout=File.open("#{filename}#{co}#{extension}" ,'w')
  puts "sachin"
end

puts "amit"

whats my problem is in last file means kabab10.txt i geeting the output like sachin and amit but i don't want amit to be come in 10th file how to solve it`

Answer 1

Try using puts to put sachin to the files.

$f = File.open("#{filename}#{co}#{extension}" ,'w')
$f.puts "sachin"

Answer 2

i edit your question but i don't think how you get amit in all your files as you using it out of the loop.But i hope following helps you if you put puts "amit" in for loop

puts "amit" if i != 10

Edited :- Do you like something like following

filename = "kabab" 
extension = ".txt" 

puts "amit"

for i in 1..10 
  $stdout=File.open("#{filename}#{i}#{extension}" ,'w')
    puts "sachin"

end

Answer 3

Don't change $stdout, and certainly not without storing away the old value somewhere so you can restore it after you're done with it.

Instead, call puts on the file object:

File.open("#{filename}#{co}#{extension}" ,'w') do |file|
  10.times do
    file.puts "sachin" # This goes to the file
  end
end

puts "amit" # This goes to standard output