views:

97

answers:

3

I need different constructors for my instances. What is a common pattern for that?

+2  A: 

Sometimes, default values for parameters is enough for multiple constructors. And when that doesn't suffice, I try to wrap most of the constructor functionality into an init(other-params) function that is called afterwards. Also consider using the factory concept to make an object that can effectively create the other objects you want.

http://en.wikipedia.org/wiki/Factory_method_pattern#Javascript

eruciform
Factory method feels like a good solution - just be sure to not confuse it with the use of a separate factory class, which probably is completely irrelevant in this use case.
Simon Groenewolt
+3  A: 

JavaScript doesn't have function overloading, including for methods or constructors.

If you want a function to behave differently depending on the number and types of parameters you pass to it, you'll have to sniff them manually. JavaScript will happily call a function with more or fewer than the declared number of arguments.

function foo(a, b) {
    if (b===undefined) // parameter was omitted in call
        b= 'some default value';

    if (typeof(a)==='string')
        this._constructInSomeWay(a, b);
    else if (a instanceof MyType)
        this._constructInSomeOtherWay(a, b);
}

You can also access arguments as an array-like to get any further arguments passed in.

If you need more complex arguments, it can be a good idea to put some or all of them inside an object lookup:

function bar(argmap) {
    if ('optionalparam' in argmap)
        this._constructInSomeWay(argmap.param, argmap.optionalparam);
    ...
}

bar({param: 1, optionalparam: 2})

Python demonstrates how default and named arguments can be used to cover the most use cases in a more practical and graceful way than function overloading. JavaScript, not so much.

bobince
A: 

How do you find this one?

function Foobar(foobar) {
    this.foobar = foobar;
}

Foobar.prototype = {
    foobar: null
};

Foobar.fromComponents = function(foo, bar) {
    var foobar = foo + bar;
    return new this(foobar);
};
codeholic